$x\le6-x$
$-3.75+2\left(-4x+6.1-3.25x\right)$
$-1^2+2\left(-1\right)+5$
$\int\frac{\left(x-1\right)}{x+4}dx$
$0^2+5$
$b\:+26b\:+\:13$
$\lim_{x\to\infty}\left(\frac{6x-1}{\sqrt{x^2+5}}\right)$
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