$x ^ { 2 } y - 2 y = x ^ { 3 } - 1$
$16x^2-4=0$
$\left(\frac{3}{4}x-\frac{1}{2}y\right)^3$
$\lim_{x\to0}-\left(\frac{1}{1-2^{\frac{1}{x}}}\right)$
$\lim_{x\to0}\left(\frac{x^3+sin\left(x\right)+2}{x^3}\right)$
$-48-3$
$\left(x+7\right)\left(y-6\right)$
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