$13\cdot14$
$\left(-4\right)x\left(+6\right)x\left(-7\right)x\left(+8\right)$
$3\left(4u\right)$
$\left(x-4\right)\:x^2+4x+16$
$\frac{dy}{dx}\left(x^3y^2+\cos\left(y\right)=x^3\right)$
$\frac{5}{\:6}x^2-\frac{1}{6}x^2-\frac{1}{3}x^2$
$9^{-5-2}$
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