$\lim_{x\to0}\left(-\frac{e^x-1}{x^3}\right)$
$y''-6y'+11y=0$
$-5<3x+10$
$\frac{d^2}{dx^2}\left(8\sqrt{x-4}\right)$
$\sqrt[3]{\sqrt[2]{\frac{a^6b^{12}}{64x^{18}}}}$
$x^2-4x\ge12$
$2.4379928\cdot2^{+16}$
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