$\frac{d}{dx}\left(\frac{\sqrt{x-1}}{\sqrt[3]{2x+3}}\right)$
$\left(-2a^2+b+3\right)\left(2a^2+2\right)$
$20+90+514a$
$-646+-328+10+245$
$10\left(x^2+x^3\right)+x^2+x^3$
$x+7\ge3-5x$
$tan^2sin^2=tan^2-sin^2$
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