$\left(2x+1\right)^3\left(x-3\right)^4$
$m^2+6m+9=0$
$\frac{28}{1}\:\frac{2\pi}{x}$
$16b^2+24bc+9c^2$
$\int\frac{\ln\left(17x\right)}{5x}dx$
$12\left(x-12\right)$
$\frac{dy}{dx}=-xy^3$
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