∫(2(x+17)5)dx\int\left(\frac{2}{\left(x+17\right)^5}\right)dx∫((x+17)52)dx
dydt=3t2y\frac{dy}{dt}=3t^2ydtdy=3t2y
sin2θ (1+tan2θ )=tan2θ sin^2\theta\:\left(1+tan^2\theta\:\right)=tan^2\theta\:sin2θ(1+tan2θ)=tan2θ
4⋅2+16xy+16xy24\cdot2+16xy+16xy24⋅2+16xy+16xy2
2x−1≤x2x-1\le x2x−1≤x
x+3>4,1x+3>4,1x+3>4,1
2a2bc2; a=2; b=3; c=12a^2bc^2;\:a=2;\:b=3;\:c=12a2bc2;a=2;b=3;c=1
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