$\frac{6}{6^3}^5$
$x+2=2x+7$
$\cot\left(m\right)\tan\left(m\right)=1$
$\sin^2e+\left(\cos e+\tan e\right)\left(\cos e-\tan e\right)-\tan^2e$
$\frac{dy}{dx}=\left(x\left(1+y\right)\right)$
$2cot\left(x\right)-1=0$
$2x+x-13$
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