$\frac{1}{v}+\frac{\left(3v+12\right)}{\left(v^2-5v\right)}=\frac{\left(7v-56\right)}{\left(v^2-5v\right)}$
$x2+5=5x$
$-x^2-6x-8$
$\sqrt[3]{x^{22}}$
$\left(m+5a\right)\left(3-5a\right)$
$\lim_{x\to5}\left(\frac{\sqrt{x-9}}{x-81}\right)$
$\int x^5\sqrt{2x^2+4}dx$
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