$\lim_{x\to\infty}\left(\frac{x}{ln\:x^2}\right)$
$\int\left(x^3+x^2\right)^5\left(3x^2+2x\right)dx$
$6+\frac{24}{2}$
$\frac{1}{y}y'\:=5$
$\frac{2+x}{x+1}=\frac{3}{4}$
$\frac{81-16x^4}{3+2x}$
$\lim_{x\to0}\left(\frac{1-x+xlnx}{x^2-2x-1}\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!