$\frac{2x+6}{2}-x=3$
$\left(7+m\right)\left(7-m\right)$
$14\cdot\left(-15\right)$
$\int\left(x^2+6\right)^{-1}xdx$
$\left(3x+80\right)\left(x-700\right)$
$\frac{2x^{0}y^{3}}{\left(x^{0}y^{3}\right)^{4}}$
$49x^2-16x^2-24x-9$
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