$10-\frac{\left(-15\right)}{-5}$
$\frac{16}{4}-\left(-5\right)$
$\left(-4-8\right)\left(4-7\right)$
$\left(16a^2b^2\right)^3$
$-\frac{\left(x-14\right)}{\left(x+6\right)}$
$1+0+0+32+256$
$\left(\frac{1}{2}x^2+\frac{3}{5}x^3\right)^2$
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