$28\:x\:6$
$\frac{\left(2x^3+10x^2+x-7\right)}{x-1}$
$-4x+10<2x-1$
$\left(h^9\right)^3$
$\lim_{x\to\infty}\left(\frac{e^{\frac{1}{x^2}}-1}{2\arctan\left(x^2-\pi\right)}\right)$
$\sqrt{\sqrt[4]{3.1416}}$
$18.15-0.05$
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