$6b^4c-\frac{1}{3}b^4c-\frac{2}{5}b^4c+\frac{1}{2}b^4c+3b^4c+\frac{1}{4}b^4c$

$\frac{d}{dx}y=x=45$

$\left(\frac{\left(3^n\right)}{n^2}\left(x-1\right)^n\right)$

$-2x+3\:-\:x-5$

$\left(\frac{3\:a^3\:b^5}{13\:c^4}\right)^2\left(\frac{26\:c^5}{9\:a^2\:b^3}\right)^2$

$x^2-5x+12=0$

$225a^2+270ab+81b^2$