$ty'+2ty=t^2,\:y\left(0\right)=2$

$\frac{d}{dx}\:\left(2x^2+2\right)\cdot\left(x-1\right)$

$9m-4=8m+3$

$\left(2a+c-3b\right)-\left(7a+4b-8c\right)$

$\lim_{x\to3}\left(\frac{\sqrt{2x-5}-1}{x+3}\right)$

$\left(4+16\right)\:-\:\left(6-3\right)$

$\left(1794.39\cdot\:\left(14-14.025\right)\cdot\:0.01\right)+1794.39$