$\left(a\:-\:3\right)\left(a^2+3a+9\right)$
$\:4r^2\:+\:8r\:+\:4$
$\frac{\frac{x}{25}}{\frac{4}{x^2}}$
$\int\left(4e^{\frac{x}{3}}\right)dx$
$16x^2-\:+4y^2$
$8a^2-24ab+18b^2$
$8y+14x$
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