3(x−6)−8(x−4)>2(7x−3)3\left(x-6\right)-8\left(x-4\right)>2\left(7x-3\right)3(x−6)−8(x−4)>2(7x−3)
2xyz; x=1; y=2z=32xyz;\:x=1;\:y=2z=32xyz;x=1;y=2z=3
kx2−104xy+16xy2kx^2-104xy+16xy^2kx2−104xy+16xy2
(y−15)2\left(y-15\right)^2(y−15)2
−4x+3y+x−2z+2y-4x+3y+x-2z+2y−4x+3y+x−2z+2y
∫x+5(x+3)(x+1)dx\int\frac{x+5}{\left(x+3\right)\left(x+1\right)}dx∫(x+3)(x+1)x+5dx
tan(θ+π2)=−cotθ\tan\left(\theta+\frac{\pi}{2}\right)=-\cot\thetatan(θ+2π)=−cotθ
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