$\frac{1-cos\left(4x\right)}{sin\left(4x\right)}$
$\int160sec^2xdx$
$\int\left(3x^2\left(x^3+7\right)^3\right)dx$
$1-\csc x\cot x$
$6g+20\:=\:2g+36$
$3^6\cdot5^6$
$\frac{cos2x}{sinx}=cosx\:cotx-sinx$
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