$6-3\cdot2+4\cdot1-5+13-8$
$\frac{8\left(x+3\right)^2}{2\left(x+3\right)}$
$\left(\frac{2x^2}{5y^4}\right)^{-2}$
$\ln\tan\left(1-x\right)$
$\left(4\:-2x^2\right)^2$
$\frac{10+3r-r^2}{r^4+2r^3}$
$\tan\left(-20\right)\cdot\cos\left(20\right)$
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