$\lim_{x\to\infty}\:\left(\sqrt{\left(x+3\right)\left(x+2\right)}-x\right)$
$4^2+2\left(4^2\right)$
$\left(x-15.6\right)^2$
$x^2+3x=6$
$\sqrt[m]{\sqrt[n]{a}}=\sqrt[mn]{a}$
$16j^2-81k^2$
$\int\frac{1.}{x\sqrt{x^2+4}}dx$
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