$f\left(x\right)=\sqrt{x}^3$
$m^2+8+4$
$x-3\le12$
$\left(5x-2\right)\cdot\left(6x^2-3x+1\right)$
$\int_0^{0.3}\left(\frac{x^3}{1\:+\:x^6}\right)\:dx$
$\int_3^72^{3x^2+5}\cdot9xdx$
$4x\:+\:5y=\:52$
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