$\tan^2\left(x\right)=\sec\left(x\right)\csc\left(x\right)\tan\left(x\right)-1$
$4-3\ln\left(2x+10\right)=12$
$\lim_{x\to1}\left(\frac{x^2+3x-10}{x^3-2x^2+x-2}\right)$
$3x^9y-4^{10}x^ay-5x^2$
$16t^2-32t-256$
$\sin x=0324$
$\left(d+2f\right)^2$
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