$\int\frac{2x^3+3}{x^3-4x}dx$
$4senb+6=8$
$\left(\frac{a^4}{4}\right)^{-\frac{1}{2}}$
$\frac{203.39285\infty}{\infty}$
$\frac{du}{dt}=e^{2u+4t},\:u\left(0\right)=6$
$5+\left(4^2+\left(7-3\left(8-2\right)\right)+5\right)$
$9\sin^2x-12\sin x=0$
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