$z^{-\frac{3}{4}}$
$\:x^2+3x+3>\:0$
$\frac{1}{2}x^3\cdot\frac{4}{5}x^4y^2$
$\left(7a^7b^6+4ut^9\right)^2$
$\left(\sqrt{4x^2}\right)\left(\sqrt{3}\right)$
$i4x-1i<5$
$\left(+8\right)x\:\left(+7\right)$
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