$\left(3x\:2\:+\:17\right)\:\left(17\:-\:3x\:2\:\right)$
$\frac{\left(4x^2-10\right)\left(4x^2+60\right)}{4}$
$\left(\frac{2x^3y}{3a^2b^4}\right)^3\left(\frac{x^2y}{a^2b^4}\right)^0$
$9+\frac{\left|6\right|}{\left|-3\right|}$
$\int\left(\frac{4x-9}{4x-5}\right)dx$
$\left(1-x^2\right)\left(1+x^2\right)$
$\int\:\frac{1}{\left(x\right)^2+4}dx$
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