$x^2y^3\left(16x^3y^{\text{4}}\right)$
$3-5\cdot\infty$
$3z^2+18z+27$
$\frac{1}{2}\int\frac{2}{2x+4}du$
$5x^2-2x+3$
$\lim_{x\to\infty}\left(\frac{2x^2-4x}{x-2}\right)$
$\frac{\tan\:^2\left(x\right)}{\sec\:\left(x\right)}=\sec\:\left(x\right)-\cos\:\left(x\right)$
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