$\int x^2+1\:+\left(\frac{1}{\:x^2+1}\right)dx$

$\int\left(ln\left(x^{12}\right)\right)^2dx$

$x^2-4x-9$

$\frac{x^2+13x+40}{x+8}$

$2x-3>4x+17$

$\left(9m^2-3n\right)^2$

$\frac{1}{\sin\left(x\right)}-\left(\frac{\cos\left(x\right)}{\sin\left(x\right)}\right)\cos\left(x\right)$