$\lim_{x\to\infty}\left(\frac{\left(3x+5\right)\left(5x+2\right)}{-\left(x-3\right)^2}\right)$
$-4^2+10^2$
$x^2-20\times\:100$
$\left(8x^2-5x+3\right)-\left(3x^2+5x\right)-\left(x^2-x-3\right)$
$54,759+\:1,22$
$\left(-4x+5\right)-\left(5x-5\right)$
$\left(z^2-4\right)^2$
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