$x^3+5x^2+2x-8:\left(x+2\right)$
$11,\:683\:+\:5,\:097\:-\:6,\:453\:-\:4,\:733$
$\frac{dy}{dx}=\left(x+1\right)^2\:y\left(0\right)=2$
$-9\cdot32$
$\left(2y^2x+3\right)dx+\left(2yx^2+4\right)dy=0$
$3x+4y=18$
$\frac{a^2-6a}{a^3+3a^2}$
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