$\int_{-\infty}^{-1}\left(e^{-2t}\right)dt$
$\frac{\sin^2}{\csc}=\sin^3$
$x e ^ { 2 y + 1 } + 1 - x = 0$
$\left(4x+13\right)^2$
$\frac{dx}{dy}=\left(x-1\right)^2$
$\left(x^2+4x+8\right)-\left(x^2-4x+8\right)$
$\frac{5x^2+28x+18}{x+5}$
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