$5x\cdot6x^3$
$\int\frac{e^{2x}}{e^x-1}dx$
$^{\frac{x^2}{\left(x^4+16\right)}}$
$\lim_{x\to\infty}\left(\frac{lnx}{x^p}\right)$
$\left(8c+d\right)^2$
$3x+4>x-7$
$4\left(x^2-3x\right)=16y-41$
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