$\int\cot^3\left(\frac{x}{4}\right)dx$
$6x^2+13x+8$
$46w+7+w-8$
$-3ab+a^2b-4a^3+5ab+3a^3-6a^2b$
$\frac{x^2+1}{x^2-1}$
$-9v^9-7$
$\frac{1}{x-5}+\frac{x}{3}=2$
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