$2\:x\:12$
$9\left(a-b\right)^2-12\left(a-b\right)+4\left(a+b\right)^2$
$3b^4c-18b^3c^2+27b^2c^3$
$\left(9+4a\right)^2$
$\frac{x+1}{x-1}=x$
$3e^{-x}\cdot\frac{dy}{dx}+x=xy^2$
$\frac{x+3}{\left(x^2+2\right)\left(x^2+5\right)}$
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