$\int_1^{\infty}\frac{1}{x\left(x^2+4\right)}dx$
$\left(6x\:\:-\:\:3y\right)\:\left(\:4x\:-\:\:5y\right)$
$\int\frac{x^3e^{-2x^4}}{e^{-2x^4}+4}dx$
$\frac{dy}{dx}=3e^x+4cos\left(x\right)$
$8x+\frac{6}{x}$
$\left(3x^4y\right)^2\cdot y^8$
$-44-\left(-11\right)-\left(17\right)$
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