$3y^2+5y+2$
$\frac{dy}{dx}\left(x^2y+y^3=\cos\left(x\right)+2y+x\right)$
$\left(x+3\right)^2=\left(2x+1\right)^2+8$
$\sec-\tan\sec+\tan=1$
$-5\cdot4-3$
$\cos\left(x\right)=\left(1+\tan^2\left(x\right)\right)\left(1-\sin^2\left(x\right)\right)$
$6x^2+4x+3$
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