$12x+4=28$
$\sqrt{24a}^5b^4$
$\left(7c+5\right)\left(7c-7\right)$
$21\cdot u^{20}\cdot\left(-3z\right)$
$\frac{8m^3+216}{2x+6}$
$6x-8>x^2$
$\frac{3}{5}+\frac{-3}{5}$
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