$\left(2x^3-4yn\right)\left(2x^3+4yn\right)$
$36x^2-25=0$
$\frac{d}{dx}y=2x^3+3x+1$
$-4x+8<-3+x$
$5w+8-w=6w$
$\frac{4x^2-8x+1}{x^3-x+6}$
$21\:+\:7\:\left[5\:-\:\left(4\:-\:1\right)\:-10\:\right]$
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