$6x^2+4x=0$
$x\left(x\:-12\right)>\left(x-4\right)^2$
$\lim_{x\to-2}\frac{2x^2-5x}{x}$
$40+x=5$
$\int2\left(ln\left(x\right)+x\right)dx$
$\left(x^2-3^3\right)$
$\frac{dy}{dx}+400y=0.002x$
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