$x^2+\frac{1}{2}x+\frac{1}{16}=\frac{4}{9}$
$4x+2$
$\left(\frac{1}{y}+1\right)dy=\left(\frac{1}{x}-1\right)dx$
$\int\left(\frac{x+1}{2x^2+4x+3}\right)dx$
$\int4sin^6\left(x\right)cos\left(x\right)dx$
$\left(z+6\right)^2$
$\frac{-4.8}{2}-3.8$
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