$\frac{d}{dy}\sqrt[3]{\frac{\left(4x+1\right)\left(x+3\right)^2}{\left(x^4+5\right)\left(x+8\right)}}$
$y=x^{-8}+x^8$
$7x-6y=42$
$8\left(-3x+2\right)<6\left(3x-11\right)$
$2\left(\frac{\sqrt{4x^2}}{2}\right)$
$\sqrt[5]{128m^{10}}$
$\left(5x+7\right)\left(3x+2y\right)$
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