$15x\frac{3}{5}$
$-a^3-25a^2+24a^3-12a+9$
$-6\cdot3^{-4}$
$18-x>5$
$\frac{u}{2}-5\le-9$
$-4b\:+\:3b\:-\:6\:=\:-4$
$\lim_{x\to\infty}\left(\frac{3x^2}{e^{8x}}\right)$
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