$\left(89\right)-\left(77\right)-\left(-36\right)+\left(-4\right)$
$sec\left(40\right)-\tan\left(40\right)$
$\left(2b-3c\right)^3$
$\int8x^3\left(2-6x^4\right)^5dx$
$\left(x^3+64\right)-\left(36\right)$
$x^2-30x-8800=0$
$4n-2$
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