$4a^2b^2-9x^2y^4$
$\frac{v}{3}-6=-15$
$\lim_{x\to0}\left(sec8\right)$
$\left(2x+3y-4\right)-\left(x-4y+1\right)$
$3\cdot\left(-2^2\right)-\left(-7^2\right)$
$\lim_{x\to\infty}\left(\frac{\ln\left(x\right)}{x^2+1}\right)$
$\int_e^{3x}dx$
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