$2x^5+3x^4-4x^3-5x^2+3x+7.x-\frac{1}{2}$
$3a^2b+9bc^2+15ab$
$\int\frac{5x-10}{\left(x+3\right)\left(x^2+4x+5\right)}dx$
$f\left(x\right)=\frac{\left(x^2-25\right)}{x+5}$
$\left(a\cdot b^2\right)^3\cdot\left(a^2\cdot b\right)^4$
$\frac{dy}{dx}=\sec^2x\tan\left(y\right)$
$6\:\int\:x^{-2}dx$
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