$\left(4b+4c\right)^2$
$0.53n+n+0.68n$
$8^{1.3333}$
$\int\frac{3x+1}{\left(x-2\right)\cdot\left(x+3\right)}$
$-3\left(2x-5\right)<5\left(2-x\right)$
$\frac{dy}{dx}=1-xy$
$\frac{x}{x-3}-\frac{4}{x}=\frac{3}{x-3}$
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