$\frac{6x^3y^3}{2x^{-3}y^{-3}}$
$\left(4p-6q\right)\:\left(4p+6q\right)$
$-16-\left(-45\right)$
$\frac{x^3-3x^2+2x^2}{2x-\frac{1}{2}}$
$\left(m-12\right)\left(m+7\right)$
$5x-3>2x+4$
$3\left(6b\right)$
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