$f\left(x\right)=\frac{x^3}{\left(1-x^4\right)^2}$
$\int\frac{\left(\sqrt{x^2-25}\right)}{x^2}dx$
$\left(\frac{x^6y^8}{x^2y^2}\right)^3$
$0.51\cdot7.4$
$-6898\:+\:-2040$
$125x^6-64y^3$
$4a^2\:-12ab\:+\:9b^2$
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