$sin^2x+7=0$
$10x\:-\:12y\:+\:8\:+12y$
$\int\frac{x^3+16}{\left(x^2+16\right)}dx$
$x^3\cdot x^6$
$\int\left(8x^3cos^2\left(x^4\right)\right)dx$
$2x^2-14x+9=0$
$6+2-4-2\left(4-8\right)+6-7$
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