$\lim_{x\to8}\left(\frac{\sqrt{x^2-5x-24}}{2x+12}\right)$
$\left(\frac{m^3}{2}+2\right)\left(\frac{m^3}{2}-2\right)$
$10y+8=-6+9y$
$6x^2+19x+26=9x^2+34x+44$
$2\cos\left(2x\right)\tan\left(2x\right)=\tan\left(x\right)$
$x+3\left(x-2\right)-6$
$\frac{dy}{dx}=\frac{x+6}{y-6}$
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