$\left(6s+3\right)\left(6s-3\right)$
$\frac{3x^2+5x-4}{x+3}$
$\csc\left(u\right)=-\frac{13}{12}$
$\frac{x}{2}\ge1$
$7^7$
$\left(-21ab^2\right)+\left(14ab^2\right)$
$\left(-6\right)^4-3\left(-6\right)^3+7\left(-6\right)+6$
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